Which of these equations are linear functions that go
through the point (0, 6)? explain your reasoning.
y = 6x
y = x + 6
y = x2 +6
y = 2x + 6

I don't think the answer exist

Step-by-step explanation:

for y=6x

when y=0, x=0 and when x=0, y=0

hence, (x,y)=(0,0)

for y=x+6

when y=0, x+6=0, x=-6 and when x=0, y=6

hence (x,y) = (-6,6)

for y=x^2+6

when x=0, y=6 and when y=0,

x^2+6=0

subtracting 6 from both sides

x^2=-6

take the square root of both sides and get

x=+ or -sqrt(-6)= + or - (2.45i)

i.e. x=+2.45i or x=-2.45i these are complex roots anyway, and its out of point.

for y=2x+6

when x=0, y=6 and when y=0,

2x+6=0,

2x=-6,

x=-3

the coordinates give (x,y)=(-3,6)

conclude

the last choice

step-by-step explanation:

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17