The equation of like ef is y= -1/2x + 6. write an equation of a line parallel to line ef in slope intercept form that contains point (0,-2)

  y = -1/2x -2

Step-by-step explanation:

The slope-intercept form of the equation for a line is ...

  y = mx + b

Comparing this to the equation you are given, you find that the given equation describes a line with a slope of -1/2 and a y-intercept of +6. The parallel line will have the same slope, so m=-1/2.

The given point is the y-intercept of the line you want, so you can use that y-value directly as the "b" in the equation you want:

  y = -1/2x -2

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it