Terry bought some gum and some candy. the number of packs of chewing gum was one more than the number of mints. the number of mints was three times the number of chocolate bars. if gum cost 6 cents a pack, mints cost 3 cents each, and chocolate bars cost 10 cents each, how many of each confection did he get for 80 cents?

Mumber of mints=x
Number of packs of chewing gum=x+1
Number of chocolate bars=y

The number of mints was three times the number of chocolate bars; then
x=3y

We can suggest this system of equations:
x=3y
6(x+1)+3x+10y=80

we can solve this system of equations by substitution method.
6(3y+1)+3(3y)+10y=80
18y+6+9y+10y=80
18y+9y+10y=80-6
37y=74
y=74/37
y=2

x=3y
x=3*(2)=6

Number of mints=x=6
number of packs of chewing gum=x+1=6+1=7
number of chocolate bars=y=2

the number of mints is 6, the number of packs of chewing gum is 7, and the number of chocolate bars is 2.

10.4 is the answer for you

The answer is 4 points