5.solve the quadratic equation.
x
2
−
10
x
+
25
=
0
x2-10x+25=0

a.
x = 5 or 
−
5
-5

b.
x = 5

c.
x = 
−
5
-5

d.
no real solution

x=5 twice

Step-by-step explanation:

x^2-10x+25=0

multiply the coefficient of x^2 and the last term

1X25=25

find two numbers you can multiply to get 25 and add to get -10

-5 + (-5)=-10 the middle term

replace -10x with -5x -5x and solve the equation

x^2-5x-5x+25=0

factorise by grouping

x(x-5)-5(x-5)=0

(x-5)(x-5)=0

Either x-5=0,x=5 or x-5=0,x=5

Therefore x=5 twice.

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58