Idon’t really get this question can someone me out

angles EFH and GFH are congruents

for the second equivalence criterion  two triangles are equivalents if they have  respectively  2 angles and 1 side congruents

the two triangles have congruents the angle right angle (HGF and HEF) and the 55 degrees angles (EFH and GFH); then they have in common the HF side.

so the triangles are congruent and so all the sides are respectively congruent,for example EH with HG:

EH=HG

s+36=7s

s+36-7s=0

s-7s=-36

-6s=-36

6s=36

s=6

sorry for my english

x + 4/7

step-by-step explanation:

use cymath