All the members of a construction crew work at the same pace. six of them working together are able to pour foundation in 22 hours.
a)how many hours would this job take if the number of workers decreased by factor of 2?
c)how many hours would this job take if the number of workers increased by factor of 4?

a) 44hrs

b)5.5hrs

Step-by-step explanation

6 workers take 22hrs

a) if the workers decreased by factor of 2, number of workers =3. The time increases by factor of 2

Therefore, 3 workers take

22*2 = 44hrs

b) if the workers increased by factor of 4,

Number of workers = 6*4= 24

The time decreases by factor of 4

Therefore, 24 workers take

22/4= 5.5 hrs

1     sepan

2     encuentren

3     tenga

4     hable

5   parezca

6   llegue

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)