If 12 cars are needed o get 36 students to the end of the road with their packs, how many cars will be able to carry 9 students to the end is the road?

3 cars

Step-by-step explanation:

If 12 cars are needed to carry 36 students,

12cars = 36

the number of cars to carry 9 students will be:

xcars = 9

cross the two equations

36x = 12 X 9

36x = 108

x = 108/36

x= 3

Therefore, 3 cars are needed to carry 9 students

OR

12 cars will carry 36 students

so 1 car will carry, (36/12)students

therefore, 1 car will carry 3 students

So, for 9 students,

9students = 9/3 = 3

is there supposed to be a picture here?

look at the picture.

1.

ef : ab = 2 : 3

gf : cb = 2 : 3

gh : cd = 2 : 3

he : da = 2 : 3

2.

∠a ≅ ∠e

∠b ≅ ∠f

∠c ≅ ∠g

∠d ≅ ∠h

3.

use pythagorean theorem:

the length of the abcd trapezoid sides:

|ab| = 3 cm

|bc| = 10 cm

|cd| = 3(3) cm = 9 cm

|da| = 8 cm

the perimeter of abcd = 3 + 10 + 9 + 8 = 30 cm

the ratio of perimeters of the tarapezoids is equal 2 : 3.

substitute:

      cross multiply

      divide both sides by 3