The force of the wind blowing on a vertical surface varies jointly as the area of the surface and the square of the velocity. if a wind of 50 mph exerts a force of 20 lb on a surface of 1/5thft2, how much force will a wind of 125 mph place on a surface of 2 ft2?

a force of 1250lb is exerted

Step-by-step explanation:

since the force of the wind varies jointly as the area of the surface and the square of the velocity,

let f = force

a = area

velocity =v

from the above statement, we find out that

----1

that is     -----2

where k is a coefficent of proportionality

since velocity of wind in mph,v =50

and force in lb = 20

and surface area =

from eqn 2

we have that

making k subject of the formula

we have that

that means that  ---3

however, when velocity = 125mph

surface area =

putting values in eqn 3 we have

hence a force of 1250lb is exerted

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

step-by-step explanation:

two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.