Jacob is at the park having a picnic and noticed a kite stuck in a tree. if the angle of elevation between the ground and the more is 55. how high was the kite flying before it got stuck if he is 25ft from the tree?

35.7 feet

Step-by-step explanation:

The figure for the given scenario is shown below.

In the triangle ΔABC, AB is the height of kite above the ground. BC is the distance of Jacob from the tree. A is position of kite. Angle C is the angle of elevation.

Let the height of kite above ground be ft.

We can find the height,, using tan of angle C.

Plug in 55° for , for AB and 25 ft for BC. Solve for . This gives,

.

Therefore, the height of flying kite before it got stuck in the tree is 35.7 ft.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15