Write the equation of a line that passes through the point (1,2) and (3,10)

the equation for the line that passes through (1,2) and (3,10) is

Explaination:

1) Apply the slope formula: y^2 - y^1 divided by x^2 - x^1.

2) y^2 is 10

y^1 is 2

x^2 is 3

x^1 is 1

3) 10 - 2 = 8

3 - 1 = 2

8/2 = 4

Slope: 4

Equation: y = 4x + b

4) Replace y with either y^2 or y^1, and replace x with either x^2 or x^1.

5) 10 = 4(3) + b

6) 10 = 12 + b

7) subtract 12 from both sides.

-2 = b

y-intercept: -2

equation: y= 4x - 2

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3