Find the slope-intercept form of the line whose slope s 5 and that passes through the point (-6,10)

The slope-intercept form of the line whose slope is 5 and that passes through the point (-6,10) is y = 5x + 40

Solution:

We have been asked to find the slope intercept form for the point (-6,10) and slope 5.

The slope intercept form of a line is given in the following way:

y = mx + c --eq1

Where m is the slope of the line and c is the y intercept of the line.

To find c we have to substitute the x and y coordinates in eq1 along with value of the slope ‘m’ of the line.

Now the equation becomes:

Now solving for c we get:

10 = -30 + c

c = 40.

So now we to get the slope intercept for we have to substitute the value of m and c in equation 1

This gives us:

y = 5x + 40

Thus the slope intercept form of the line is y = 5x + 40

30 units^2

step-by-step explanation:

area is l × w

the length is 3

and the width is 10

3 × 10= 30 units squared