What is the solution to the following system of linear equations?

4y − 36 = −12x
3x + y = −9

Given system of linear equation 4y – 36 = -12x  and 3x + y = -9 do not have any solution.

Solution:

Need to determine solution of following system of linear equations

4y – 36 = -12x

3x + y = -9

lets modify given equation in standard form

12x + 4y -36 = 0      -------(1)

3x + y + 9 = 0         -------(2)

Lets first analyze whether given system of equation is having solution or not.

are two equation and then the given system of equation has no solution

In our case

This is condition of no solution.

Hence given system of linear equation 4y – 36 = -12x and 3x + y = -9 do not have any solution.

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.