Find the range of possible values for a measurement of 36

Let side a = 5.  Let side b = 9.  Then the triangle has

sides

a=5, b=9, and c=?.  Any side of a triangle must be less

than the other two sides added together, so

a < b+c, b < a+c, and c < a+b

Substituting:

5 < 9+c, 9 < 5+c, and c < 5+9

Solving all three for c:

-4 < c, 4 < c, c < 14

The first one is of course true, so ignore it.

Put the second and third together and get

4 < c < 14

That's it. c must be more than 4 and less than 14.

2. 7 and 14

Let side a = 7.  Let side b = 14.  Then the triangle

has sides

a=7, b=14, and c=?.  Any side of a triangle must be less

than the other two sides added together, so

a < b+c, b < a+c, and c < a+b

Substituting:

7 < 14+c, 14 < 7+c, and c < 7+14

Solving all three for c:

-7 < c, 7 < c, c < 21

The first one is of course true, so ignore it.

Put the second and third together and get

7 < c < 21

That's it. c must be more than 7 and less than 21.

3. 8 and 13

Let side a = 8.  Let side b = 13.  Then the triangle

has sides

a=8, b=13, and c=?.  Any side of a triangle must be less

than the other two sides added together, so

a < b+c, b < a+c, and c < a+b

Substituting:

8 < 13+c, 13 < 8+c, and c < 8+13

Solving all three for c:

-5 < c, 5 < c, c < 21

The first one is of course true, so ignore it.

Put the second and third together and get

5 < c < 21

That's it. c must be more than 5 and less than 21.

4. 10 and 12

Let side a = 10.  Let side b = 12.  Then the triangle

has sides

a=10, b=12, and c=?.  Any side of a triangle must be less

than the other two sides added together, so

a < b+c, b < a+c, and c < a+b

Substituting:

10 < 12+c, 12 < 10+c, and c < 10+12

Solving all three for c:

-2 < c, 2 < c, c < 22

The first one is of course true, so ignore it.

Put the second and third together and get

2 < c < 22

That's it. c must be more than 2 and less than 22.

They are all done the same way. You can do the other half

by yourself.

the y will be in still but your answer will be y x 3

step-by-step explanation:

jk: )

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: