In a certain town, the amount of sulfur oxide in the air, s, in tons, is related to the town’s population, p, in people. the relationship is s2 = 1 10 p2 + 20p + 600 the town’s population is growing at a rate, with respect to time, of 10 people/month. at what rate, with respect to time, is the amount of sulfur oxide in the air changing, when the population is 100?

Change in sulfur oxide in the air =

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate,  = 10 people per month

Now,

change in sulfur oxide with time i.e

differentiating the given relation with respect to time 't'

we have

=    + 20

at P = 100 and    = 10 people per month

we have

= 2 × 110 × 100 × 10 + 20

or

= 220020

or

=

or

Change in sulfur oxide in the air =

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

175

step-by-step explanation:

2 inches x 10 miles = 200 miles - 3 inches = 175