Consider the following game: a drum contains 10 balls, each numbered from 1 to 10. three balls are randomly drawn, without replacement, from the drum. prior to the draw, you fill out a card by selecting three numbers from 1 to 10. to win a prize, the numbers you select have to correspond to the numbers of the balls drawn, in any order. what is the probability of winning a prize?

1/120

Step-by-step explanation: First to calculate the probability, we must know the possible number of way that 3 balls can be drawn from 10 balls numbered 1-10, and the number of ways that the 3 numbers selected from the player will match the number the numbers that the player chose.

To get the total number of outcomes this entails 10C3

From the formula nCr = n!/(r!(n-r)!)

10C3= 10!/(3!(10-3)!)

10! = 10*9*8*7*6*5*4*3*2*1 = 3628800

3! = 3*2*1 = 6

(10-3)! = 7! = 7*6*5*4*3*2*1 = 5040

10C3 = 3628800/(6*5040) = 120

Of all the 120 outcomes possible, only one outcome is expected to match all the 3 numbers that the player had written down, hence the probability for winning the draw will be

3C3/10C3

=1/120 = 0.0083333333333

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

idk

step-by-step explanation: