Find a formula for the general term an (not the partial sum) of each infinite series (with starting point of n = 1.) (a) 5 4 + 5 16 + 5 64 + 5 256 + an = 5 4n (b) 1 1 + 5 2 + 25 4 + 125 8 + an = ( 5 2)n−1 (c) 1 + 7 1 − 2 + 7 2 · 1 + 3 + 7 3 · 2 · 1 − 4 + 7 4 · 3 · 2 · 1 + an = (−1)n−1 n+7 n! (d) 8 12 + 1 + 3 22 + 1 + 8 32 + 1 + 3 42 + 1 + an = 15−(1)n−1 2(n2+1)

it is c, trust i got your back lol

step-by-step explanation:

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places

answer: -10

step-by-step explanation:

s(t) = 1 - 10t

s(x) = 1 - 10x

s(x + h) = 1 - 10(x + h)

            = 1 - 10x - 10h

s(x + h) - s(x) = 1 - 10x - 10h - (1 - 10x)

                      = 1 - 10x - 10h - 1 + 10x

                      = -10h

= -10