In the diagram, −→− bisects ∠ .

if the m∠=jkm(2−22)° and m∠lkm=(6+5)° , solve for x and find ∠jkm .

x = 9 and ∠ JKM = 59°.

Step-by-step explanation:

See the attached diagram with this question.

∠ JKL is bisected by line KM.

Therefore, angle JKM = angle MKL

Now, ∠ JKM is given to be ( x² - 22 )  and ∠ LKM = ( 6x + 5 ).

So, x² - 22 = 6x + 5

⇒ x² - 6x -27 = 0

⇒ ( x - 9 ) ( x + 3 ) = 0

Therefore, x = 9 or - 3.

∠ JKM = x² - 22 = 59° for x = 9 and ∠ JKM = x² - 22 = - 13° for x = - 3

Since angle JKM can not be negative, so, x = 9 and ∠ JKM = 59°. (Answer)

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: