What four consecutive intergers have a sum of -34

-7, -8 , -9 and -10 are such four integers.

Step-by-step explanation:

Let the first integer = k

So, the next three consecutive integers are ( k+1), ((k + 1) + 1)  and (((k + 1) + 1) +1)

or, k , (k +1), (k +2) and (k +3) are four consecutive integers.

Now, their sum is -34.

⇒k   + (k +1) +  (k +2) +  (k +3)  = -34

or, 4k  + 6 = -34

or, 4k = - 34 - 6 = -40

⇒  k = -40/ 4 = -10

Hence, the first integer k = -10

The next integer = k + 1 = -10 + 1 = -9

Similarly next two integers are -8 and - 7.

So -7, -8 , -9 and -10 are such four integers.

i think ur answer is   (3,-1)

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.