Data on pull-off force (pounds) for connectors used in an automobile engine application are as follows:

79.9 75.1 78.2 74.1 73.9 75.0 77.6 77.3 73.8 74.6 75.5 74.0 74.7
75.9 72.6 73.8 74.2 78.1 75.4 76.3 75.3 76.2 74.9 78.0 75.1 76.8

(a) calculate a point estimate of the mean pull-off force of all connectors in the population (round the answer to four decimal places (e. g. 90.

(b) calculate a point estimate of the pull-off force value that separates the weakest 50% of the connectors in the population from the strongest 50% (express the answer to two decimal place (e. g. 90.

a) 75.62

b) 75.2

Step-by-step explanation:

Data provided:

79.9,75.1,78.2,74.1,73.9,75.0,77.6,77.3,73.8,74.6,75.5,74.0,74.7,75.9,72.6,73.8,74.2,78.1,75.4,76.3,75.3,76.2,74.9,78.0,75.1,76.8

Sum = 1966.3

Total number of observations, n = 26

a) Mean is given as:

Mean =

or

Mean =

or

Mean = 75.62

b) For value that separates the weakest 50% of the connectors i.e median or the 50th percentile

Arranging the data in ascending order:

72.6, 73.8, 73.8, 73.9, 74, 74.1, 74.2, 74.6, 74.7, 74.9, 75, 75.1, 75.1, 75.3, 75.4, 75.5, 75.9, 76.2, 76.3, 76.8, 77.3, 77.6, 78, 78.1, 78.2, 79.9

i =

or

i =  = 13

When the number of observations is even the formula for median is:

or

or

or

or

Median = 75.2

the answer is 510

step-by-step explanation:

15 • 13 = 195

15 • 12 = 180

15 • 5 = 75

12 • 5 = 60

195 + 180 = 375

375 + 75 = 450

450 + 60 = 510

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1