Suppose j varies jointly with g and v, and j=2 when g=4 and v=3.
find j when g=8 and v=9.

Step-by-step explanation:

we know that

In a join variation, If j varies jointly with respect to g and v, the equation will be of the form

where k is a constant

step 1

Find the value of k

we have

j=2,g=4,v=3

substitute and solve for k

The equation is equal to

step 2

Find the value of j when g=8,v=9

substitute the values in the equation and solve for j

2/3

step-by-step explanation:

the slope of a line is equal to the rise/run. in this case the line rises 2 units for every +3 units it moves

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for