Consider an inductive definition of a version of ackermann’s function. this function was named after wilhelm ackermann, a german mathematician who was a student of the great mathematician david hilbert. ackermann’s function plays an important role in the theory of recursive functions and in the study of the complexity of certain algorithms involving set unions. (there are several different variants of this function. all are called ackermann’s function and have similar properties even though their values do not always agree.) a (m, n)=⎧⎩⎨2n, if m=0 0, if m≥1, n=0 2, if m≥1, n=1 a (m−1, a (m, n−1)) if m≥1 , n≥2 find these values of ackermann’s function

blue marble is 15 times out of 50 = 15/50 reduces to 3/10

landing on tails is 24 out of 50 = 24/50 reduces to 12/25

to find the probability of both multiply together:

3/10 x 12/25 = 3 x 12 / 10 x 25 = 36/250

if you multiplied the numerator and denominator by 10 you get 360/2500.

the answer is 360/2500

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation:

aloha~! my name is zalgo and i am here to you out on this amazing day. to answer your question, yes, nonzero numbers can have a greatest common factor and that would be 1. still don't get it? let me considering every number is divisible by 1 and hence every number has 1 as a factor of theirs. so, if 2 nonzero numbers didn't share any gcf (greatest common factor), they would still have a factor in common and that would be 1.

i hope that this ! : p

"stay and stay proud! " - zalgo

(by the way, do you mind marking me as brainliest? i'd greatly appreciate it! mahalo! x3)