The mayor of a town has proposed a plan for the annexation of a new community. a political study took a sample of 900 voters in the town and found that 76% of the residents favored annexation. using the data, a political strategist wants to test the claim that the percentage of residents who favor annexation is above 73% . make the decision to reject or fail to reject the null hypothesis at the 0.10 level.

Reject the null hypothesis

Step-by-step explanation:

The proportion of t voters in the sample of 900 voters that favored annexation is 76% = 0.76, so we can estimate the standard deviation as

The mean according to the sample is 76% of 900  

= 0.76*900 = 684

The stated mean is 73% of 900  

= 0.73*900 = 657

We have then the hypothesis

: The mean is 657

: The mean is greater than 657

This is a right-tailed test.

Our critical value at the 0.10 level is  

= 1.282 (The area of the Normal N(0,1) for z > 1.282 is less than 0.10. This value is obtained with tables or computer)

The zone of rejection is z > 1.282

Our z-statistic is

Since 2.107 > 1.282 we reject the null hypothesis.

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation