How do you solve −6x+14< −28 and3x+28≤25minus, 6, x, plus, 14, is less than, minus, 28, start color #ed5fa6, start text, space, a, n, d, end text, end color #ed5fa6, 3, x, plus, 28, is less than or equal to, 25
choose 1 choose 1 (choice a)
a x\leq-1x≤−1x, is less than or equal to, minus, 1 or x> 7x> 7x, is greater than.
b -1\leq x< 7−1≤x< 7minus, 1, is less than or equal to, x, is less than.
c x< 7x< 7x, is less than.
d there are no solutions.
e all values of xxx are solutions.

D There are no solutions.

Step-by-step explanation:

First you must note that we solve inequalities just like normal equation, the only difference is that the sign of inequality will change whenever we multiply both sides by a minus sign or reciprocate both sides.

To solve -6x+14<-28

Subtract 14 from both sides,

= -6x+14-14<-28-14

= -6x<-42

Multiplying both sides by minus we have;

= 6x>42 (Note that the sign changed to greater than)

Dividing both sides by 6, we have

x>7 or 7<x(1)

Similarly for 3x+28≤25

Subtracting 28 from both sides we have;

3x+28-28≤25-28

3x≤-3

x≤-1...(2)

Combining (1) and (2) inequalities, we have 7<x≤-1

Therefore, there are no solutions

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8  

can you complete your sentence? i could !