Astudent is taking a multiple-choice exam in which each question has five choices. assuming that she has no knowledge of the correct answers to any of the questions, she has decided on a strategy in which she will place five balls into a box. she randomly selects one ball for each question and replaces the ball in the box. the marking on the ball will determine her answer to the question. there are six multiple-choice questions on the exam. complete parts (a) through (d) below. a. what is the probability that she will get six questions correct? (round to four decimal places as needed.)b. what is the probability that she will get at least five questions correct? (round to four decimal places as needed.)c. what is the probability that she will get no questions correct? (round to four decimal places as needed.)d. what is the probability that she will get no more than two questions correct?

Step-by-step explanation:

A student is taking a multiple-choice exam in which each question has five choices. Assuming that she has no knowledge of the correct answers to any of the questions, she has decided on a strategy in which she will place five balls into a box. She randomly selects one ball for each question and replaces the ball in the box. The marking on the ball will determine her answer to the question. There are six multiple-choice questions on the exam. Complete parts (a) through (d) below.a. What is the probability that she will get six questions correct?(Round to four decimal places as needed.)b. What is the probability that she will get at least five questions correct?(Round to four decimal places as needed.)c. What is the probability that she will get no questions correct?(Round to four decimal places as needed.)d. What is the probability that she will get no more than two questions correct?

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

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