Dan has bags of candy with two pieces in each. bill has bags of candy with five pieces in each. bill has six more bags than dan. the total number of pieces candy the two boys have 100. how many bags does bill have?

Bill has bags of candy with five pieces in each. The Bill has 16 bags

Solution:

Given, Dan has bags of candy with two pieces in each.  

Bill has bags of candy with five pieces in each.  

Bill has six more bags than Dan.  

Then, number of bags with bill = 6 + number of bags with dan.

The total number of pieces candy the two boys have 100.  

Now, candies with bill + candies with dan = 100

⇒ 5 pieces per bag x number of bags with bill + 2 pieces per bag x number of bags with dan = 100

⇒ 5 x (6 + number of bags with dan) + 2 x number of bags with dan = 100

⇒ 30 + 5 x number of bags with dan + 2 x number of bags with dan = 100

⇒ (5  + 2) x number of bags with dan = 100 – 30

⇒ 7 x number of bags with dan = 70

⇒ Number of bags with dan = 10

So, number of bags with bill = 6 + 10 = 16

Hence, bill has 16 bags.

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.

a

step-by-step explanation:

the answer is a