Identify the relative maximum value of g(x) for the function shown below.
g(x)=x^3-3x^2+2

To find the relative maximum value of the function we need to find where the function has its first derivative equal to 0.

Its first derivative is -7*(2x)/(x^2+5)^2

7*(2x)/(x^2+5)^2 =0 the numerator needs to be eqaul to 0

2x=0

x=0

g(0) = 7/5

The relative maximum value is at the point (0, 7/5).

Step-by-step explanation:

7.3

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)