Assume that a national fitness study reports that 5% of millenials exercise daily. suppose that a researcher surveys a random sample of 120 millenials regarding their daily exercise habits. assume that is a binomial random variable that represents the number of millenials in the sample who exercise daily. compute the mean and standard deviation of the sampling distribution of . report as a whole number and as a decimal precise to two decimal places.

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

33

step-by-step explanation: g=6

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step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6