Solve and show work

(2x^2-4xy+2y^2)(3x-4)

Step-by-step explanation: Distribute sum groups.

2{x}^{2}(3x-4)-4xy(3x-4)+2{y}^{2}(3x-4)2x

2

(3x−4)−4xy(3x−4)+2y

2

(3x−4)

Expand.

6{x}^{3}-8{x}^{2}-4xy(3x-4)+2{y}^{2}(3x-4)6x

3

−8x

2

−4xy(3x−4)+2y

2

(3x−4)

Expand.

6{x}^{3}-8{x}^{2}-(12{x}^{2}y-16xy)+2{y}^{2}(3x-4)6x

3

−8x

2

−(12x

2

y−16xy)+2y

2

(3x−4)

Expand.

6{x}^{3}-8{x}^{2}-(12{x}^{2}y-16xy)+6{y}^{2}x-8{y}^{2}6x

3

−8x

2

−(12x

2

y−16xy)+6y

2

x−8y

2

Remove parentheses.

6{x}^{3}-8{x}^{2}-12{x}^{2}y+16xy+6{y}^{2}x-8{y}^{2}6x

3

−8x

2

−12x

2

y+16xy+6y

2

x−8y

2

Hope this helps!

2 is the final ! : )

50x5=$250

step-by-step explanation: