X+ y = 0
3x - 2y = 10
which of the following ordered pairs (x, y) satisfies
the system of equations above?
a) (3,-2)
b) (2,-2)
c) (-2,2)
d) (-2,-2)

The solution of x + y = 0  and 3x - 2y = 10 is (2, -2) and option b is correct.

Solution:

Given, two lines of equations are x + y = 0 and 3x – 2y = 10.

We have to find the solution of the given two line of equations.

Now, take x + y = 0 → y = - x

Substitute y value in other equation.

→ 3x – 2y = 10 → 3x – 2(-x) = 10 → 3x + 2x = 10 → 5x = 10 → x = 2

Then, y = -x → y = -(2) → y = -2.

So, the solution of the given two equations will be (2, -2).

Hence, solution is (2, -2) and option b is correct.

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation:

step-by-step explanation:

well if you round, things become much more simple. round 5.95 to 6, 4.25 to 4, and 1.05 to 1. now, add 6+4+1 and that would equal 11. so the items together would equal to about $11.