Find the zeros of the function.
f(x) = 9x^3 - 45x^2 + 36x

The zeros of the function f(x) = 9x^3 - 45x^2 + 36x is 0, 1, 4

Solution:

Given that

For finding the zeros of the function, we equate the entire function to zero i.e.,

Dividing throughout by 9, we get

Taking x as common throughout the equation, we get  

Thus, by factorization of the above equation, we get 0 = x(x - 1)(x - 4)

Now ,equating the factors we got to 0, we get      

x = 0, x - 1 = 0, x - 4 = 0

x = 0, x = 1, x = 4

Thus, the zeros of the above given function are 0, 1, 4

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

4400

step-by-step explanation: