Prove that triangle awm is congruent to triangle cpm using a two column proof

ΔAWM ≅ ΔCPM proved

Step-by-step explanation:

See the given diagram with this question.

We have to prove ΔAWM ≅ ΔCPM

Now, (i) M is the mid point of AC, so AM =MC

(ii) Now, W is the mid point of AB, hence, AW = WB =

Again, P is the mid point of BC i.e

Now, it is given that BP = PM = MW = WB

Hence, BP = WB , hence, AW = PC

(iii) Again, PM = MW

Therefore, from the SSS rule, it is proved that ΔAWM ≅ ΔCPM. (Answer)

f

step-by-step explanation:

f

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions