Ajet left the airport and flew south. a passenger plane left one hour later flying 52mph faster in an effort to catch up to it. after seven hours the passenger plane finally caught up. find the jet’s average speed

Jet average speed was 45.5 miles per hour.

Solution:

Given that a jet left airport and flew south. A passenger plane left one hour later flying at 52 miles per hour trying to catch up the jet.

After seven hours passenger plane caught up jet.

So distance travelled by passenger plane in 7 hours is same as distance travelled by jet in 7 + 1 = 8 hours as jet plane left 1 hour early.

Distance travelled by passenger plane = speed x time = 52 x 7 = 364 miles  

So same distance that is 364 miles is travelled by jet plane in 8 hours.

=> Speed of jet = = 45.5 miles per hour.

Hence jet average speed was 45.5 miles per hour.

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.