What is log squared with a base of 4 with the exponent (x^2+x) and the whole thing is equal to 0.25. find the domain of x and find what x is equal to.

X = 1 , -2

Step-by-step explanation:

Given in question as,

(log4(x² + x))² = 0.25

log4(x² + x) = 0.5

Applying log base property if      log(a)X = b,   then X =a^b

Or, x² + x = 4^0.5

     x² + x = 2

     x² + x - 2 = 0

     x²+2x-x-2 = 0

     (x + 2) (x - 1) = 0

So, x = 1 and -2   Answer

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)