Aphotographer sells large photos for $27 profit and small photos for an $11 profit. this past year, she sold 126 photos and made a profit of $2,250.how many of each size photo did she sell?

She sold 72 small photos and 54 large photos.

Step-by-step explanation:

We can set a equations system with the given information. Let X be the quantity of small photos and Z large photos.

We are told that she sold 126 photos in total, so:

X + Z = 126

Also, she earned 2,250 by selling certain quantities of small photo and large photos, so:

$2,250 = $11X + $27Z

From the first equation we get that X=126-Z, replace that into the 2nd equation:

2,250 = 11(126-Z) +27Z

2,250 = 1,386 - 11Z + 27Z

2,250 - 1,386 = 16Z

864 = 16Z

Z = 864/16

Z = 54 is the number of large photos sold. Now find X.

X = 126 - Z

X = 126 - 54

X = 72 is the number of small photos sold.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

r = 78539458390583095803458309458039485093485 or just 3

step-by-step explanation: