In δjkl, the measure of ∠l=90°, lj = 33 feet, and jk = 58 feet. find the measure of ∠k to the nearest tenth of a degree.

∠K = 29.6°

Step-by-step explanation:

The diagram is shown below:

From the triangle, JK = 58 feet and LJ = 33 feet. ∠L = 90°.

So, the triangle ΔJKL is a right angled triangle.

Now, for the triangle ΔJKL, tan of the angle K is given as:

∴∠K = °

So, the measure of angle K is ∠K = 29.6° to the nearest tenth of a degree.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)