In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays. find the probability that he did not hit a boundary.

The probability of NOT hitting a boundary is (4/5).

Step-by-step explanation:

Let E: Be the event of hitting a boundary

now, Probability of any event E =  

Here, number of favorable outcomes = 6

So, P(E)  =

⇒Probability of hitting a six is 1/5

Now, P(E)  + P(not E)  = 1

So, P(not hitting a boundary ) = 1  -  P(hitting a boundary)

= 1 - (1/5)  = 4/5

Hence, the probability of NOT hitting a boundary is (4/5).