The distribution of the diameters of a particular variety of oranges is approximately normal with a standard deviation of 0.3 inch. how does the diameter of an orange at the 67^th percentile compare with the mean diameter?
a) 0.201 inch below the mean
b) 0.132 inch below the mean
c) 0.132 inch above the mean
d) 0.201 inch above the mean
e) 0.440 inch above the mean

The correct answer is C.

Step-by-step explanation:

percentile is represented as the value of probability in the norma distribution.

We look for a z-value with a left-tail of 0.67.

z=0.44

where,

M: mean

SD: standar deviation

x=z×SD+M=0.44×0.3+M=M+0.132

The diameter of an orange at the 67^th percentile is 0.132 inch above the mean.

idk

step-by-step explanation:

the functions have the same rate of change i think. i narrowed it down to this answer and "the rate of change of tour 1 is greater" but i got it wrong using that answer so im assuming its the answer above. (this is a question i also answered from the iready site if anyone needs a reference)