The sum of two numbers is 54. the smaller number is 8 less than the larger number. what are the numbers?

The smaller number is 8 less than the larger number. The numbers are 23 and 31

Solution:

Let the bigger of the two numbers whose sum is 54 be x

Let the other number i.e., the smaller number be y

Also, it is given the smaller number is 8 less than the larger number i.e., x – 8

Thus, y = x - 8

Now, it is given that the sum of the two numbers is 54

Thus, it can be written in the equation form as:

x + y = 54

(x) + (x - 8) = 54

2x - 8 = 54

2x = 62

x = 31

Therefore, for  x i.e, the larger number equal to 31, y i.e, the small number equal to y = x - 8

i.e, y = 31 - 8 = 23

Thus, the numbers, as mentioned above, whose sum is given as 54 are 23 and 31.

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

50-60=10

step-by-step explanation: