Acircular cylinder has a radius between 5.50 and 6.00 cm and a volume of 225 cm3. write an inequality that represents the range of possible heights the cylinder can have to meet this criterion to the nearest hundrenth of the centimeter.

The answer is: 1.99<h<2.37

Step-by-step explanation:

The procedure is as followed

V=πr^2h

225=π(5.5)^2h

h=2.37

225=π(6)^2h

h=1.99

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

move it to the other side

step-by-step explanation: