The probability is 1% that an electrical connector that is kept dry fails during the warranty period of a portable computer. if the connector is ever wet, the probability of a failure during the warranty period is 5%. if 90% of the connectors are kept dry and 10% are wet, what proportion of connectors fail during the warranty period? let: d = electrical connector is dry d' = electrical connector is not kept dry (i. e., is wet) f = connector fails during warranty period f' = connector does not fail during warranty period match the correct probability description to each given probability value

0.014 or 1.4% of connectors fail during the warranty period.

Step-by-step explanation:

Consider the provided information.

Let: D = electrical connector is dry

D' = electrical connector is not kept dry (i.e., is wet)

F = connector fails during warranty period

F' = connector does not fail during warranty period

90% of the connectors are kept dry

That means P(D)=0.9

10% are wet,

P(D')=0.1

The probability is 1% that an electrical connector that is kept dry fails during the warranty period, i.e.

P(F|D)=0.01

If the connector is ever wet, the probability of a failure during the warranty period is 5%, i.e.

P(F|D')=0.05

Hence, 0.014 or 1.4% of connectors fail during the warranty period.

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10