Amarketing consultant observed 40 consecutive shoppers to estimate the average money spent by shoppers in a supermarket store. assume that the money spent by the population of shoppers follow a normal distribution with a standard deviation of $21.51. what is the probability that the average money spent by a sample of 40 shoppers is within $10 of the actual population mean. 0.1389

P (average within 10) = 0.9984

Step-by-step explanation:

Given:

Number of consecutive shoppers observed, n = 40

Standard deviation, σ = $21.51

Now,

Standard error (SE) =

or

Standard error (SE) =

or

Standard error (SE) = 3.40

also,

z =

on substituting the values, we have

z =

or

z = 2.94

Now, from the Table of Area Under Standard Noral Curve

for z = 2.94 ; area = 0.9984

we have P (average within 10) = 0.9984

c > -10.55

step-by-step explanation:

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!