Solve for x in the equation x^2+2x+1=17

x= (-1+ √17) or (-1-√17)

Step-by-step explanation:

In this question, we have to solve for x from the given equation x² +2x+1 =17

Now, the equation can be rearranged to x² +2x -16 =0.

Here we can not apply the process of factorization to get the value of x.

Hence, we will use the Shridhar Acharya formula to solve the value of x.

{This formula gives, if ax² +bx +c =0 then, the value of x can be solved as

x=[-b±√(b²-4ac)]/2a }

Hence, in this case, the solution for x will be

x=

⇒ x=

⇒ x= (-1+ √17) or (-1-√17) (Answer)

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is