Kayson is looking at two buildings, building a and building b, at an angle of elevation of 73°. building a is 30 feet away, and building b is 35 feet away. which building is taller and by approximately how many feet?

The Building B is taller than Building A and by 16.354 feet ≈16 feet.

Step-by-step explanation:

Kayson is looking at building A at an angle of elevation of 73° and building A is 30 feet away from him.

So, if the height of the building A is x feet, then we can write,  

tan 73°=x/30, ⇒x =30 tan73° =98.125 feet.

Again, Kayson is looking at building B at an angle of elevation of 73° and building B is 35 feet away from him.

So, if the height of the building B is y feet, then we can write,

tan 73° =y/35, ⇒ y= 35 tan73° = 114.479 feet.

Therefore, Building B is taller than Building A and by (114.479-98.125) =16.354 feet ≈16 feet. (Answer)

cause it equals more