Thirty percent of all telephones of a certain type are submitted for service while under warranty. of these, 70% can be repaired, whereas the other 30% must be replaced with new units. if a company purchases ten of these telephones, what is the probability that exactly three will end up being replaced under warranty? (round your answer to three decimal places.)

0.2669~0.267

Step-by-step explanation:

Given that Thirty percent of all telephones of a certain type are submitted for service while under warranty.

Let x be the no of units being replaced out of 10 units purchased by a company under warranty

We have X has two outcomes either replaced or not.  Also each unit is independent of the other

P(each unit fails and requires replaement ) = p =0.3

q =0.7

the probability that exactly three will end up being replaced under warranty

=P(X=3)

= ~0.267

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn

step-by-step explanation:

1. practice, practice & more practice

2. review errors

3. master the key concepts

do not try to memorise the processes.

4. understand your doubts.

5. create a distraction free study environment

6. create a mathematical dictionary

7. apply maths to real world problems.