Jack is 27 years older than susan. in 5 years, he will be 4 times as old as she is.
a. find the present ages of jack and susan.
b. what calculations would you do to check if your answer is correct?

susan´s age=4

jack´s age=31

Step-by-step explanation:

Hello!

To solve the first part of this problem we must propose a system of equations of 2 x2, that is to say two equations with two unknowns where

J = is the age of jack

S = susan's age

with the above the following two equations are inferred

ecuation 1

J=S+27

ecuation 2

(J+5)=4(s+5)

J=4S+20-5

J=4S+15

now to solve we subtract equation 1 from equation 2 as follows

J=4S  +  15

-

J=S   +  27

___________

0=4S-S+15-27

0=3S-12

susan is 4 years old

now we use the ecuation number 1

J=S+27

J=4+27=31

jack is 31 years old

b.

Finally, to verify that the answer is correct, we replace the ages of jack and susan in equation 2.

(J+5)=4(s+5)

(31+5)=4(4+5)

36=36

as the equation is the same means that our answer is correct

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

i need more details

step-by-step explanation: