Solve each radical equation. be sure to check your solutionsa)√(x+5)-9=-12b)√(4x-7)=√( 3x+9)

a) There is no solution to the equation.

b) Solution: x = 16

Step-by-step explanation:

Hi there!

a) Let´s write the equation:

√(x + 5) - 9 = -12

add 9 to both sides of the equation

√(x + 5) = -12 + 9

√(x + 5) = -3

Square both sides of the equation

x + 5 = 9

Subtract 5 to both sides

x = 9 - 5

x = 4

Let´s check the solution:

√(x + 5) - 9 = -12

√(4 + 5) - 9 = -12

√9 - 9 = -12

3 - 9 = -12

-6 ≠ -12

Then x = 4 is not a solution to the equation.

b) Let´s write the equation:

√(4x - 7) = √(3x + 9)

square both sides of the equation  

4x - 7 = 3x + 9

subtract 3x and add 7 to both sides of the equation

4x - 3x = 9 + 7

x = 16

Let´s check the solution:

√(4x - 7) = √(3x + 9)

x = 16

√(4(16) - 7) = √(3(16) + 9)

√57 = √57

Then x = 16 is the solution to the equation

a negative exponent is translated as follows:

so, we have

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.