If f(x) = 2x - 4 and g(x)= x², what is f(g(
oa) x²- 4
ob) x² + 2x - 4
oc) 2x³ - 4
od) 2x² - 4

D

Step-by-step explanation:

To evaluate f(g(x)) substitute x = g(x) into f(x)

f(g(x))

= f(x²)

= 2(x²) - 4 = 2x² - 4

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

1 + (6 / x - 1)

step-by-step explanation:

divide using polynomial division.