Lisa brought half of her savings to the bakery and bought 12 croissants for $14.20. the amount of money she brings home with her is more than $2.00. use an inequality to find how much money she had in her savings before going to the bakery. (write the inequality that represents the situation, and solve it.)

Before going to the bakery, Lisa had more than $32.40.

Step-by-step explanation:

Hi there!

Let x be Lisa´s savings.

She brings half of her savings to the bakery and expends $14.20. What is left is more than $2.00. Then:

x/2 - 14.2 > 2

Let´s solve the inequality:

x/2 - 14.2 > 2

Add 14.2 to both sides of the inequality.

x/2 > 2 + 14.2

x/2 > 16.2

Multiply by 2 both sides of the inequality.

x > 32.4

Before going to the bakery, Lisa had more than $32.40.

answer: it is 1: 47 pm

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.