2.11 a concert is performed for a crowd of 118
people. adult tickets cost $20 each, student tickets
cost $16 each, and children tickets cost $11.50 each.
the revenue for the concert is $1745.00. there are
40 more children at the concert than students. how
many of each type of ticket are sold?

Number of Students who attended = 22

Number of Adults who attended = 34

Number of Children who attended = 62

Step-by-step explanation:

Total crowd at concert  =  118

Cost of each adult's ticket = $20

Cost of each student's ticket = $16

Cost of each children's ticket = $11.50

The total revenue of the concert = $1745.00

Now, Let the number of students = k

So, the number of children = k + 40

So, number of adults = 118  - {k + (k + 40)}

                                   = 118- 2k -40 = 78 -2k

So, the total revenue = Total revenue from {adults + students + children}

or, $1745.00 = (78 -2k)(20) +  k(16)  +(k+40)(11.50)

here, solving for the value of k :

12.5k = 2020 -  1745

or k = 275\12.5 = 22

So, the Number of students who attended = 22

Number of Adults who attended = 78 - 2k = 78 - 44 = 34

Number of children who attended = k + 40 = 22 + 40 = 62

i think the answer is fried chicken ; >

step-by-step explanation:

if you was gonna solve for a, a is a   < -12