Simplify each of the problems.

a·a²·a³

(6x²⁵)

(3x³)(3x⁴²)

18c³ ÷ -3c²

9a³b⁵ ÷ -3ab²

(x²)⁷

(-2x⁴)⁵

8x⁰

6x·3x⁵·x⁰

-18

-27

-6

-3

-32

8

6x .3x^{5} . x⁰    = 18 x^{6}

Step-by-step explanation:

-18

-27

-6

-3

-32

8

6x .3x^{5} . x⁰  =   = 18 x^{6}

When we multiply powers then they get added like in the first question.

When they are powered further then they're multiplied.

1) a. a² a³ = a⁶

2) (6 ) (-3 )  =  -18

3)  (3 ) (3 ) (-3 ) =      =-27

4)  18c³ ÷ -3c²  =  -6c

5) 9a³b⁵ ÷ -3ab² =      = -3 a²b³

6) ( )⁷ =  

7) ( -2 [ ] )⁵ =   = -2

8) 8x⁰ = 8

9) 6x .3 . x⁰  =   = 18

 Step-by-step explanation:

1) a . a².a³

= a¹ x a²x a³

= a¹⁺²⁺³

= a⁶

2) (6 ) (-3 )

   = -18

    =  -18

3) (3 ) (3 ) (-3 )

    = -27

    =-27

4) 18c³ ÷ -3c²

    =  - c

     =  -6c

5) 9a³b⁵ ÷ -3ab²

    = -3 a²b³

6) ( )⁷

 =

7) ( -2 [ ] )⁵

 = -2

8) 8x⁰ = 8 x 1 = 8

9) 6x .3 . x⁰

  = 18

9) 6x .3 . x⁰

 = 18

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!